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3(x-4)-2(x-5)=6-2(x-5)
We move all terms to the left:
3(x-4)-2(x-5)-(6-2(x-5))=0
We multiply parentheses
3x-2x-(6-2(x-5))-12+10=0
We calculate terms in parentheses: -(6-2(x-5)), so:We add all the numbers together, and all the variables
6-2(x-5)
determiningTheFunctionDomain -2(x-5)+6
We multiply parentheses
-2x+10+6
We add all the numbers together, and all the variables
-2x+16
Back to the equation:
-(-2x+16)
x-(-2x+16)-2=0
We get rid of parentheses
x+2x-16-2=0
We add all the numbers together, and all the variables
3x-18=0
We move all terms containing x to the left, all other terms to the right
3x=18
x=18/3
x=6
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