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3(x-4)-2=2(2x+5)-2
We move all terms to the left:
3(x-4)-2-(2(2x+5)-2)=0
We multiply parentheses
3x-(2(2x+5)-2)-12-2=0
We calculate terms in parentheses: -(2(2x+5)-2), so:We add all the numbers together, and all the variables
2(2x+5)-2
We multiply parentheses
4x+10-2
We add all the numbers together, and all the variables
4x+8
Back to the equation:
-(4x+8)
3x-(4x+8)-14=0
We get rid of parentheses
3x-4x-8-14=0
We add all the numbers together, and all the variables
-1x-22=0
We move all terms containing x to the left, all other terms to the right
-x=22
x=22/-1
x=-22
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