3(x-4)-3(3x+4)=4(3-x)+5x+4

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Solution for 3(x-4)-3(3x+4)=4(3-x)+5x+4 equation: 



3(x-4)-3(3x+4)=4(3-x)+5x+4

We move all terms to the left:

3(x-4)-3(3x+4)-(4(3-x)+5x+4)=0

We add all the numbers together, and all the variables

3(x-4)-3(3x+4)-(4(-1x+3)+5x+4)=0

We multiply parentheses

3x-9x-(4(-1x+3)+5x+4)-12-12=0



We calculate terms in parentheses: -(4(-1x+3)+5x+4), so:

4(-1x+3)+5x+4

We add all the numbers together, and all the variables

5x+4(-1x+3)+4

We multiply parentheses

5x-4x+12+4

We add all the numbers together, and all the variables

x+16

Back to the equation:

-(x+16)



We add all the numbers together, and all the variables

-6x-(x+16)-24=0

We get rid of parentheses

-6x-x-16-24=0

We add all the numbers together, and all the variables

-7x-40=0

We move all terms containing x to the left, all other terms to the right

-7x=40

x=40/-7

x=-5+5/7

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