3(x-4)-4(x-3)=x+2-(x-5)

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Solution for 3(x-4)-4(x-3)=x+2-(x-5) equation: 



3(x-4)-4(x-3)=x+2-(x-5)

We move all terms to the left:

3(x-4)-4(x-3)-(x+2-(x-5))=0

We multiply parentheses

3x-4x-(x+2-(x-5))-12+12=0



We calculate terms in parentheses: -(x+2-(x-5)), so:

x+2-(x-5)

determiningTheFunctionDomain
x-(x-5)+2

We get rid of parentheses

x-x+5+2

We add all the numbers together, and all the variables

7

Back to the equation:

-(7)



We add all the numbers together, and all the variables

-1x-7=0

We move all terms containing x to the left, all other terms to the right

-x=7

x=7/-1

x=-7

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