3(x-4)-4(x-3)=x+3(x-5)

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Solution for 3(x-4)-4(x-3)=x+3(x-5) equation: 



3(x-4)-4(x-3)=x+3(x-5)

We move all terms to the left:

3(x-4)-4(x-3)-(x+3(x-5))=0

We multiply parentheses

3x-4x-(x+3(x-5))-12+12=0



We calculate terms in parentheses: -(x+3(x-5)), so:

x+3(x-5)

We multiply parentheses

x+3x-15

We add all the numbers together, and all the variables

4x-15

Back to the equation:

-(4x-15)



We add all the numbers together, and all the variables

-1x-(4x-15)=0

We get rid of parentheses

-1x-4x+15=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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