3(x-4)-4(x-3)=x+4-(x-4)

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Solution for 3(x-4)-4(x-3)=x+4-(x-4) equation: 



3(x-4)-4(x-3)=x+4-(x-4)

We move all terms to the left:

3(x-4)-4(x-3)-(x+4-(x-4))=0

We multiply parentheses

3x-4x-(x+4-(x-4))-12+12=0



We calculate terms in parentheses: -(x+4-(x-4)), so:

x+4-(x-4)

determiningTheFunctionDomain
x-(x-4)+4

We get rid of parentheses

x-x+4+4

We add all the numbers together, and all the variables

8

Back to the equation:

-(8)



We add all the numbers together, and all the variables

-1x-8=0

We move all terms containing x to the left, all other terms to the right

-x=8

x=8/-1

x=-8

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