3(x-4)-4(x-3)=x+5-(x-3)

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Solution for 3(x-4)-4(x-3)=x+5-(x-3) equation: 



3(x-4)-4(x-3)=x+5-(x-3)

We move all terms to the left:

3(x-4)-4(x-3)-(x+5-(x-3))=0

We multiply parentheses

3x-4x-(x+5-(x-3))-12+12=0



We calculate terms in parentheses: -(x+5-(x-3)), so:

x+5-(x-3)

determiningTheFunctionDomain
x-(x-3)+5

We get rid of parentheses

x-x+3+5

We add all the numbers together, and all the variables

8

Back to the equation:

-(8)



We add all the numbers together, and all the variables

-1x-8=0

We move all terms containing x to the left, all other terms to the right

-x=8

x=8/-1

x=-8

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