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3(x-4)-5(x-3)=x-2-(3x-5)
We move all terms to the left:
3(x-4)-5(x-3)-(x-2-(3x-5))=0
We multiply parentheses
3x-5x-(x-2-(3x-5))-12+15=0
We calculate terms in parentheses: -(x-2-(3x-5)), so:We add all the numbers together, and all the variables
x-2-(3x-5)
determiningTheFunctionDomain x-(3x-5)-2
We get rid of parentheses
x-3x+5-2
We add all the numbers together, and all the variables
-2x+3
Back to the equation:
-(-2x+3)
-2x-(-2x+3)+3=0
We get rid of parentheses
-2x+2x-3+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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