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3(x-4)-5=-2(x-6)
We move all terms to the left:
3(x-4)-5-(-2(x-6))=0
We multiply parentheses
3x-(-2(x-6))-12-5=0
We calculate terms in parentheses: -(-2(x-6)), so:We add all the numbers together, and all the variables
-2(x-6)
We multiply parentheses
-2x+12
Back to the equation:
-(-2x+12)
3x-(-2x+12)-17=0
We get rid of parentheses
3x+2x-12-17=0
We add all the numbers together, and all the variables
5x-29=0
We move all terms containing x to the left, all other terms to the right
5x=29
x=29/5
x=5+4/5
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