3(x-4)-7=-3(-8x+1)-7x

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Solution for 3(x-4)-7=-3(-8x+1)-7x equation: 



3(x-4)-7=-3(-8x+1)-7x

We move all terms to the left:

3(x-4)-7-(-3(-8x+1)-7x)=0

We multiply parentheses

3x-(-3(-8x+1)-7x)-12-7=0



We calculate terms in parentheses: -(-3(-8x+1)-7x), so:

-3(-8x+1)-7x

We add all the numbers together, and all the variables

-7x-3(-8x+1)

We multiply parentheses

-7x+24x-3

We add all the numbers together, and all the variables

17x-3

Back to the equation:

-(17x-3)



We add all the numbers together, and all the variables

3x-(17x-3)-19=0

We get rid of parentheses

3x-17x+3-19=0

We add all the numbers together, and all the variables

-14x-16=0

We move all terms containing x to the left, all other terms to the right

-14x=16

x=16/-14

x=-1+1/7

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