3(x-4)-8=4(4+x)

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Solution for 3(x-4)-8=4(4+x) equation:



3(x-4)-8=4(4+x)
We move all terms to the left:
3(x-4)-8-(4(4+x))=0
We add all the numbers together, and all the variables
3(x-4)-(4(x+4))-8=0
We multiply parentheses
3x-(4(x+4))-12-8=0
We calculate terms in parentheses: -(4(x+4)), so:
4(x+4)
We multiply parentheses
4x+16
Back to the equation:
-(4x+16)
We add all the numbers together, and all the variables
3x-(4x+16)-20=0
We get rid of parentheses
3x-4x-16-20=0
We add all the numbers together, and all the variables
-1x-36=0
We move all terms containing x to the left, all other terms to the right
-x=36
x=36/-1
x=-36

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