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3(x-4)-9=2(x-6)=
We move all terms to the left:
3(x-4)-9-(2(x-6))=0
We multiply parentheses
3x-(2(x-6))-12-9=0
We calculate terms in parentheses: -(2(x-6)), so:We add all the numbers together, and all the variables
2(x-6)
We multiply parentheses
2x-12
Back to the equation:
-(2x-12)
3x-(2x-12)-21=0
We get rid of parentheses
3x-2x+12-21=0
We add all the numbers together, and all the variables
x-9=0
We move all terms containing x to the left, all other terms to the right
x=9
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