3(x-4)/4=6(2x-3)/3

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Solution for 3(x-4)/4=6(2x-3)/3 equation: 



3(x-4)/4=6(2x-3)/3

We move all terms to the left:

3(x-4)/4-(6(2x-3)/3)=0

We calculate fractions


3x/()+(-(6(2x-3)*4)/()=0



We calculate terms in parentheses: +(-(6(2x-3)*4)/(), so:

-(6(2x-3)*4)/(

We multiply all the terms by the denominator


-(6(2x-3)*4)



We calculate terms in parentheses: -(6(2x-3)*4), so:

6(2x-3)*4

We multiply parentheses

48x-72

Back to the equation:

-(48x-72)



We get rid of parentheses

-48x+72

Back to the equation:

+(-48x+72)



We get rid of parentheses

3x/()-48x+72=0

We multiply all the terms by the denominator


3x-48x*()+72*()=0

We add all the numbers together, and all the variables

3x-48x*()=0

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