3(x-4)/7=1-3x

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Solution for 3(x-4)/7=1-3x equation:



3(x-4)/7=1-3x
We move all terms to the left:
3(x-4)/7-(1-3x)=0
We add all the numbers together, and all the variables
3(x-4)/7-(-3x+1)=0
We get rid of parentheses
3(x-4)/7+3x-1=0
We multiply all the terms by the denominator
3(x-4)+3x*7-1*7=0
We add all the numbers together, and all the variables
3(x-4)+3x*7-7=0
We multiply parentheses
3x+3x*7-12-7=0
Wy multiply elements
3x+21x-12-7=0
We add all the numbers together, and all the variables
24x-19=0
We move all terms containing x to the left, all other terms to the right
24x=19
x=19/24
x=19/24

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