3(x-4)=-18+6x

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Solution for 3(x-4)=-18+6x equation: 



3(x-4)=-18+6x

We move all terms to the left:

3(x-4)-(-18+6x)=0

We add all the numbers together, and all the variables

3(x-4)-(6x-18)=0

We multiply parentheses

3x-(6x-18)-12=0

We get rid of parentheses

3x-6x+18-12=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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