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3(x-4)=-2(-x+1)-1
We move all terms to the left:
3(x-4)-(-2(-x+1)-1)=0
We add all the numbers together, and all the variables
3(x-4)-(-2(-1x+1)-1)=0
We multiply parentheses
3x-(-2(-1x+1)-1)-12=0
We calculate terms in parentheses: -(-2(-1x+1)-1), so:We get rid of parentheses
-2(-1x+1)-1
We multiply parentheses
2x-2-1
We add all the numbers together, and all the variables
2x-3
Back to the equation:
-(2x-3)
3x-2x+3-12=0
We add all the numbers together, and all the variables
x-9=0
We move all terms containing x to the left, all other terms to the right
x=9
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