3(x-4)=-7(x+2)+30

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Solution for 3(x-4)=-7(x+2)+30 equation: 



3(x-4)=-7(x+2)+30

We move all terms to the left:

3(x-4)-(-7(x+2)+30)=0

We multiply parentheses

3x-(-7(x+2)+30)-12=0



We calculate terms in parentheses: -(-7(x+2)+30), so:

-7(x+2)+30

We multiply parentheses

-7x-14+30

We add all the numbers together, and all the variables

-7x+16

Back to the equation:

-(-7x+16)



We get rid of parentheses

3x+7x-16-12=0

We add all the numbers together, and all the variables

10x-28=0

We move all terms containing x to the left, all other terms to the right

10x=28

x=28/10

x=2+4/5

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