3(x-4)=-9(x+2)+27

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Solution for 3(x-4)=-9(x+2)+27 equation: 



3(x-4)=-9(x+2)+27

We move all terms to the left:

3(x-4)-(-9(x+2)+27)=0

We multiply parentheses

3x-(-9(x+2)+27)-12=0



We calculate terms in parentheses: -(-9(x+2)+27), so:

-9(x+2)+27

We multiply parentheses

-9x-18+27

We add all the numbers together, and all the variables

-9x+9

Back to the equation:

-(-9x+9)



We get rid of parentheses

3x+9x-9-12=0

We add all the numbers together, and all the variables

12x-21=0

We move all terms containing x to the left, all other terms to the right

12x=21

x=21/12

x=1+3/4

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