3(x-4)=-x+68

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Solution for 3(x-4)=-x+68 equation: 



3(x-4)=-x+68

We move all terms to the left:

3(x-4)-(-x+68)=0

We add all the numbers together, and all the variables

3(x-4)-(-1x+68)=0

We multiply parentheses

3x-(-1x+68)-12=0

We get rid of parentheses

3x+1x-68-12=0

We add all the numbers together, and all the variables

4x-80=0

We move all terms containing x to the left, all other terms to the right

4x=80

x=80/4

x=20

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