3(x-4)=12-4x+9+15+4x+3

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Solution for 3(x-4)=12-4x+9+15+4x+3 equation: 



3(x-4)=12-4x+9+15+4x+3

We move all terms to the left:

3(x-4)-(12-4x+9+15+4x+3)=0

We add all the numbers together, and all the variables

3(x-4)-39=0

We multiply parentheses

3x-12-39=0

We add all the numbers together, and all the variables

3x-51=0

We move all terms containing x to the left, all other terms to the right

3x=51

x=51/3

x=17

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