3(x-4)=12x-12+x

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Solution for 3(x-4)=12x-12+x equation: 



3(x-4)=12x-12+x

We move all terms to the left:

3(x-4)-(12x-12+x)=0

We add all the numbers together, and all the variables

3(x-4)-(13x-12)=0

We multiply parentheses

3x-(13x-12)-12=0

We get rid of parentheses

3x-13x+12-12=0

We add all the numbers together, and all the variables

-10x=0

x=0/-10

x=0

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