3(x-4)=14x+10

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Solution for 3(x-4)=14x+10 equation: 



3(x-4)=14x+10

We move all terms to the left:

3(x-4)-(14x+10)=0

We multiply parentheses

3x-(14x+10)-12=0

We get rid of parentheses

3x-14x-10-12=0

We add all the numbers together, and all the variables

-11x-22=0

We move all terms containing x to the left, all other terms to the right

-11x=22

x=22/-11

x=-2

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