3(x-4)=16+x

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Solution for 3(x-4)=16+x equation: 



3(x-4)=16+x

We move all terms to the left:

3(x-4)-(16+x)=0

We add all the numbers together, and all the variables

3(x-4)-(x+16)=0

We multiply parentheses

3x-(x+16)-12=0

We get rid of parentheses

3x-x-16-12=0

We add all the numbers together, and all the variables

2x-28=0

We move all terms containing x to the left, all other terms to the right

2x=28

x=28/2

x=14

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