3(x-4)=19-5(1+2x)

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Solution for 3(x-4)=19-5(1+2x) equation:



3(x-4)=19-5(1+2x)
We move all terms to the left:
3(x-4)-(19-5(1+2x))=0
We add all the numbers together, and all the variables
3(x-4)-(19-5(2x+1))=0
We multiply parentheses
3x-(19-5(2x+1))-12=0
We calculate terms in parentheses: -(19-5(2x+1)), so:
19-5(2x+1)
determiningTheFunctionDomain -5(2x+1)+19
We multiply parentheses
-10x-5+19
We add all the numbers together, and all the variables
-10x+14
Back to the equation:
-(-10x+14)
We get rid of parentheses
3x+10x-14-12=0
We add all the numbers together, and all the variables
13x-26=0
We move all terms containing x to the left, all other terms to the right
13x=26
x=26/13
x=2

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