3(x-4)=2(-2x+11)

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Solution for 3(x-4)=2(-2x+11) equation: 



3(x-4)=2(-2x+11)

We move all terms to the left:

3(x-4)-(2(-2x+11))=0

We multiply parentheses

3x-(2(-2x+11))-12=0



We calculate terms in parentheses: -(2(-2x+11)), so:

2(-2x+11)

We multiply parentheses

-4x+22

Back to the equation:

-(-4x+22)



We get rid of parentheses

3x+4x-22-12=0

We add all the numbers together, and all the variables

7x-34=0

We move all terms containing x to the left, all other terms to the right

7x=34

x=34/7

x=4+6/7

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