3(x-4)=2(-2x+2)

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Solution for 3(x-4)=2(-2x+2) equation: 



3(x-4)=2(-2x+2)

We move all terms to the left:

3(x-4)-(2(-2x+2))=0

We multiply parentheses

3x-(2(-2x+2))-12=0



We calculate terms in parentheses: -(2(-2x+2)), so:

2(-2x+2)

We multiply parentheses

-4x+4

Back to the equation:

-(-4x+4)



We get rid of parentheses

3x+4x-4-12=0

We add all the numbers together, and all the variables

7x-16=0

We move all terms containing x to the left, all other terms to the right

7x=16

x=16/7

x=2+2/7

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