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3(x-4)=2(-2x-1)
We move all terms to the left:
3(x-4)-(2(-2x-1))=0
We multiply parentheses
3x-(2(-2x-1))-12=0
We calculate terms in parentheses: -(2(-2x-1)), so:We get rid of parentheses
2(-2x-1)
We multiply parentheses
-4x-2
Back to the equation:
-(-4x-2)
3x+4x+2-12=0
We add all the numbers together, and all the variables
7x-10=0
We move all terms containing x to the left, all other terms to the right
7x=10
x=10/7
x=1+3/7
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