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3(x-4)=2(2-x)-1
We move all terms to the left:
3(x-4)-(2(2-x)-1)=0
We add all the numbers together, and all the variables
3(x-4)-(2(-1x+2)-1)=0
We multiply parentheses
3x-(2(-1x+2)-1)-12=0
We calculate terms in parentheses: -(2(-1x+2)-1), so:We get rid of parentheses
2(-1x+2)-1
We multiply parentheses
-2x+4-1
We add all the numbers together, and all the variables
-2x+3
Back to the equation:
-(-2x+3)
3x+2x-3-12=0
We add all the numbers together, and all the variables
5x-15=0
We move all terms containing x to the left, all other terms to the right
5x=15
x=15/5
x=3
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