3(x-4)=2(2x-3)+1

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Solution for 3(x-4)=2(2x-3)+1 equation: 



3(x-4)=2(2x-3)+1

We move all terms to the left:

3(x-4)-(2(2x-3)+1)=0

We multiply parentheses

3x-(2(2x-3)+1)-12=0



We calculate terms in parentheses: -(2(2x-3)+1), so:

2(2x-3)+1

We multiply parentheses

4x-6+1

We add all the numbers together, and all the variables

4x-5

Back to the equation:

-(4x-5)



We get rid of parentheses

3x-4x+5-12=0

We add all the numbers together, and all the variables

-1x-7=0

We move all terms containing x to the left, all other terms to the right

-x=7

x=7/-1

x=-7

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