3(x-4)=2(3-2x)

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Solution for 3(x-4)=2(3-2x) equation: 



3(x-4)=2(3-2x)

We move all terms to the left:

3(x-4)-(2(3-2x))=0

We add all the numbers together, and all the variables

3(x-4)-(2(-2x+3))=0

We multiply parentheses

3x-(2(-2x+3))-12=0



We calculate terms in parentheses: -(2(-2x+3)), so:

2(-2x+3)

We multiply parentheses

-4x+6

Back to the equation:

-(-4x+6)



We get rid of parentheses

3x+4x-6-12=0

We add all the numbers together, and all the variables

7x-18=0

We move all terms containing x to the left, all other terms to the right

7x=18

x=18/7

x=2+4/7

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