3(x-4)=2(3x-1)

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Solution for 3(x-4)=2(3x-1) equation: 



3(x-4)=2(3x-1)

We move all terms to the left:

3(x-4)-(2(3x-1))=0

We multiply parentheses

3x-(2(3x-1))-12=0



We calculate terms in parentheses: -(2(3x-1)), so:

2(3x-1)

We multiply parentheses

6x-2

Back to the equation:

-(6x-2)



We get rid of parentheses

3x-6x+2-12=0

We add all the numbers together, and all the variables

-3x-10=0

We move all terms containing x to the left, all other terms to the right

-3x=10

x=10/-3

x=-3+1/3

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