3(x-4)=2(7-x)+6

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Solution for 3(x-4)=2(7-x)+6 equation: 



3(x-4)=2(7-x)+6

We move all terms to the left:

3(x-4)-(2(7-x)+6)=0

We add all the numbers together, and all the variables

3(x-4)-(2(-1x+7)+6)=0

We multiply parentheses

3x-(2(-1x+7)+6)-12=0



We calculate terms in parentheses: -(2(-1x+7)+6), so:

2(-1x+7)+6

We multiply parentheses

-2x+14+6

We add all the numbers together, and all the variables

-2x+20

Back to the equation:

-(-2x+20)



We get rid of parentheses

3x+2x-20-12=0

We add all the numbers together, and all the variables

5x-32=0

We move all terms containing x to the left, all other terms to the right

5x=32

x=32/5

x=6+2/5

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