3(x-4)=2(x-3)+4x

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Solution for 3(x-4)=2(x-3)+4x equation: 



3(x-4)=2(x-3)+4x

We move all terms to the left:

3(x-4)-(2(x-3)+4x)=0

We multiply parentheses

3x-(2(x-3)+4x)-12=0



We calculate terms in parentheses: -(2(x-3)+4x), so:

2(x-3)+4x

We add all the numbers together, and all the variables

4x+2(x-3)

We multiply parentheses

4x+2x-6

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

3x-6x+6-12=0

We add all the numbers together, and all the variables

-3x-6=0

We move all terms containing x to the left, all other terms to the right

-3x=6

x=6/-3

x=-2

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