3(x-4)=2(x-3)+x-6

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Solution for 3(x-4)=2(x-3)+x-6 equation: 



3(x-4)=2(x-3)+x-6

We move all terms to the left:

3(x-4)-(2(x-3)+x-6)=0

We multiply parentheses

3x-(2(x-3)+x-6)-12=0



We calculate terms in parentheses: -(2(x-3)+x-6), so:

2(x-3)+x-6

We add all the numbers together, and all the variables

x+2(x-3)-6

We multiply parentheses

x+2x-6-6

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

3x-3x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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