3(x-4)=2x(6+x)

Solution for 3(x-4)=2x(6+x) equation:

3(x-4)=2x(6+x)

We move all terms to the left:

3(x-4)-(2x(6+x))=0

We add all the numbers together, and all the variables

3(x-4)-(2x(x+6))=0

We multiply parentheses

3x-(2x(x+6))-12=0


We calculate terms in parentheses: -(2x(x+6)), so:

2x(x+6)

We multiply parentheses

2x^2+12x

Back to the equation:

-(2x^2+12x)


We get rid of parentheses

-2x^2+3x-12x-12=0

We add all the numbers together, and all the variables

-2x^2-9x-12=0

a = -2; b = -9; c = -12;
Δ = b2-4ac
Δ = -92-4·(-2)·(-12)
Δ = -15
Delta is less than zero, so there is no solution for the equation