3(x-4)=2x+8+x-20

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Solution for 3(x-4)=2x+8+x-20 equation: 


Simplifying
3(x + -4) = 2x + 8 + x + -20

Reorder the terms:
3(-4 + x) = 2x + 8 + x + -20
(-4 * 3 + x * 3) = 2x + 8 + x + -20
(-12 + 3x) = 2x + 8 + x + -20

Reorder the terms:
-12 + 3x = 8 + -20 + 2x + x

Combine like terms: 8 + -20 = -12
-12 + 3x = -12 + 2x + x

Combine like terms: 2x + x = 3x
-12 + 3x = -12 + 3x

Add '12' to each side of the equation.
-12 + 12 + 3x = -12 + 12 + 3x

Combine like terms: -12 + 12 = 0
0 + 3x = -12 + 12 + 3x
3x = -12 + 12 + 3x

Combine like terms: -12 + 12 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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