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3(x-4)=4(2x-7)
We move all terms to the left:
3(x-4)-(4(2x-7))=0
We multiply parentheses
3x-(4(2x-7))-12=0
We calculate terms in parentheses: -(4(2x-7)), so:We get rid of parentheses
4(2x-7)
We multiply parentheses
8x-28
Back to the equation:
-(8x-28)
3x-8x+28-12=0
We add all the numbers together, and all the variables
-5x+16=0
We move all terms containing x to the left, all other terms to the right
-5x=-16
x=-16/-5
x=3+1/5
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