3(x-4)=5-2(x+1)

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Solution for 3(x-4)=5-2(x+1) equation: 



3(x-4)=5-2(x+1)

We move all terms to the left:

3(x-4)-(5-2(x+1))=0

We multiply parentheses

3x-(5-2(x+1))-12=0



We calculate terms in parentheses: -(5-2(x+1)), so:

5-2(x+1)

determiningTheFunctionDomain
-2(x+1)+5

We multiply parentheses

-2x-2+5

We add all the numbers together, and all the variables

-2x+3

Back to the equation:

-(-2x+3)



We get rid of parentheses

3x+2x-3-12=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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