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3(x-4)=5/2x
We move all terms to the left:
3(x-4)-(5/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3(x-4)-(+5/2x)=0
We multiply parentheses
3x-(+5/2x)-12=0
We get rid of parentheses
3x-5/2x-12=0
We multiply all the terms by the denominator
3x*2x-12*2x-5=0
Wy multiply elements
6x^2-24x-5=0
a = 6; b = -24; c = -5;
Δ = b2-4ac
Δ = -242-4·6·(-5)
Δ = 696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{696}=\sqrt{4*174}=\sqrt{4}*\sqrt{174}=2\sqrt{174}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{174}}{2*6}=\frac{24-2\sqrt{174}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{174}}{2*6}=\frac{24+2\sqrt{174}}{12} $
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