3(x-4)=6(2x-2)

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Solution for 3(x-4)=6(2x-2) equation:



3(x-4)=6(2x-2)
We move all terms to the left:
3(x-4)-(6(2x-2))=0
We multiply parentheses
3x-(6(2x-2))-12=0
We calculate terms in parentheses: -(6(2x-2)), so:
6(2x-2)
We multiply parentheses
12x-12
Back to the equation:
-(12x-12)
We get rid of parentheses
3x-12x+12-12=0
We add all the numbers together, and all the variables
-9x=0
x=0/-9
x=0

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