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3(x-4)=6(x-5)
We move all terms to the left:
3(x-4)-(6(x-5))=0
We multiply parentheses
3x-(6(x-5))-12=0
We calculate terms in parentheses: -(6(x-5)), so:We get rid of parentheses
6(x-5)
We multiply parentheses
6x-30
Back to the equation:
-(6x-30)
3x-6x+30-12=0
We add all the numbers together, and all the variables
-3x+18=0
We move all terms containing x to the left, all other terms to the right
-3x=-18
x=-18/-3
x=+6
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