3(x-4)=6x+12

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Solution for 3(x-4)=6x+12 equation: 



3(x-4)=6x+12

We move all terms to the left:

3(x-4)-(6x+12)=0

We multiply parentheses

3x-(6x+12)-12=0

We get rid of parentheses

3x-6x-12-12=0

We add all the numbers together, and all the variables

-3x-24=0

We move all terms containing x to the left, all other terms to the right

-3x=24

x=24/-3

x=-8

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