3(x-4)=6x+17

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Solution for 3(x-4)=6x+17 equation: 



3(x-4)=6x+17

We move all terms to the left:

3(x-4)-(6x+17)=0

We multiply parentheses

3x-(6x+17)-12=0

We get rid of parentheses

3x-6x-17-12=0

We add all the numbers together, and all the variables

-3x-29=0

We move all terms containing x to the left, all other terms to the right

-3x=29

x=29/-3

x=-9+2/3

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