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3(x-4)=6x-(3x-12)
We move all terms to the left:
3(x-4)-(6x-(3x-12))=0
We multiply parentheses
3x-(6x-(3x-12))-12=0
We calculate terms in parentheses: -(6x-(3x-12)), so:We get rid of parentheses
6x-(3x-12)
We get rid of parentheses
6x-3x+12
We add all the numbers together, and all the variables
3x+12
Back to the equation:
-(3x+12)
3x-3x-12-12=0
We add all the numbers together, and all the variables
-24!=0
There is no solution for this equation
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