3(x-4)=8x+68-4x

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Solution for 3(x-4)=8x+68-4x equation: 



3(x-4)=8x+68-4x

We move all terms to the left:

3(x-4)-(8x+68-4x)=0

We add all the numbers together, and all the variables

3(x-4)-(4x+68)=0

We multiply parentheses

3x-(4x+68)-12=0

We get rid of parentheses

3x-4x-68-12=0

We add all the numbers together, and all the variables

-1x-80=0

We move all terms containing x to the left, all other terms to the right

-x=80

x=80/-1

x=-80

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