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3(x-5)(x-5)=-27
We move all terms to the left:
3(x-5)(x-5)-(-27)=0
We add all the numbers together, and all the variables
3(x-5)(x-5)+27=0
We multiply parentheses ..
3(+x^2-5x-5x+25)+27=0
We multiply parentheses
3x^2-15x-15x+75+27=0
We add all the numbers together, and all the variables
3x^2-30x+102=0
a = 3; b = -30; c = +102;
Δ = b2-4ac
Δ = -302-4·3·102
Δ = -324
Delta is less than zero, so there is no solution for the equation
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