3(x-5)+2(4x-1)=31

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Solution for 3(x-5)+2(4x-1)=31 equation: 



3(x-5)+2(4x-1)=31

We move all terms to the left:

3(x-5)+2(4x-1)-(31)=0

We multiply parentheses

3x+8x-15-2-31=0

We add all the numbers together, and all the variables

11x-48=0

We move all terms containing x to the left, all other terms to the right

11x=48

x=48/11

x=4+4/11

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