3(x-5)+2=9(x-3)-6x+42

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Solution for 3(x-5)+2=9(x-3)-6x+42 equation: 



3(x-5)+2=9(x-3)-6x+42

We move all terms to the left:

3(x-5)+2-(9(x-3)-6x+42)=0

We multiply parentheses

3x-(9(x-3)-6x+42)-15+2=0



We calculate terms in parentheses: -(9(x-3)-6x+42), so:

9(x-3)-6x+42

We add all the numbers together, and all the variables

-6x+9(x-3)+42

We multiply parentheses

-6x+9x-27+42

We add all the numbers together, and all the variables

3x+15

Back to the equation:

-(3x+15)



We add all the numbers together, and all the variables

3x-(3x+15)-13=0

We get rid of parentheses

3x-3x-15-13=0

We add all the numbers together, and all the variables

-28!=0

There is no solution for this equation

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