3(x-5)+4(x+1)=31

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Solution for 3(x-5)+4(x+1)=31 equation: 



3(x-5)+4(x+1)=31

We move all terms to the left:

3(x-5)+4(x+1)-(31)=0

We multiply parentheses

3x+4x-15+4-31=0

We add all the numbers together, and all the variables

7x-42=0

We move all terms containing x to the left, all other terms to the right

7x=42

x=42/7

x=6

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