3(x-5)+7=8-4(2x+3)

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Solution for 3(x-5)+7=8-4(2x+3) equation: 



3(x-5)+7=8-4(2x+3)

We move all terms to the left:

3(x-5)+7-(8-4(2x+3))=0

We multiply parentheses

3x-(8-4(2x+3))-15+7=0



We calculate terms in parentheses: -(8-4(2x+3)), so:

8-4(2x+3)

determiningTheFunctionDomain
-4(2x+3)+8

We multiply parentheses

-8x-12+8

We add all the numbers together, and all the variables

-8x-4

Back to the equation:

-(-8x-4)



We add all the numbers together, and all the variables

3x-(-8x-4)-8=0

We get rid of parentheses

3x+8x+4-8=0

We add all the numbers together, and all the variables

11x-4=0

We move all terms containing x to the left, all other terms to the right

11x=4

x=4/11

x=4/11

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